Hai ,
in a textbox am having text as
"(20/100)+pay1*pay2" .it's a formula. and stored in a particular
variable.
string strformula="(20/100)+pay1*pay2" ;
i've to substitute the value of the variable 'pay1' & 'pay2' and
finding the value of that strformula.
can any onr tell me how to find 'pay1' and 'pay2' in the variable
strformula. it's urgent and reply immediately.
Thanks in advance.Hi
I am not sure what this has to do with SQL Server!
If the strings are unique then you could use the replace function.
John
<ksrajalakshmi@.gmail.com> wrote in message
news:1139642884.262422.60580@.g14g2000cwa.googlegroups.com...
> Hai ,
> in a textbox am having text as
> "(20/100)+pay1*pay2" .it's a formula. and stored in a particular
> variable.
> string strformula="(20/100)+pay1*pay2" ;
> i've to substitute the value of the variable 'pay1' & 'pay2' and
> finding the value of that strformula.
> can any onr tell me how to find 'pay1' and 'pay2' in the variable
> strformula. it's urgent and reply immediately.
> Thanks in advance.
>|||If am having the value as
string strvalue ="(12.23+233.56)*12/100";
i've to find the value.so that am converting to double. but it throws
error. tel me how to find value?|||Hi
It is still not clear if you are using SQL Server! If you are then you can
do something like:
DECLARE @.strformula nvarchar(60)
DECLARE @.nparams nvarchar(80)
DECLARE @.output decimal(10,4)
DECLARE @.pay1 decimal(10,4)
DECLARE @.pay2 decimal(10,4)
SET @.strformula = N'SELECT @.output_val = (20.0/100)+(@.pay_1*@.pay_2)'
SET @.nparams = N'@.output_val decimal(10,4) OUTPUT, @.pay_1 decimal(10,4),
@.pay_2 decimal(10,4)'
SET @.pay1 = 233.56
SET @.pay2 = 12.0/100
SELECT @.strformula
SELECT @.nparams
EXEC sp_executesql @.strformula, @.nparams, @.output_val = @.output OUTPUT,
@.pay_1 = @.pay1, @.pay_2 = @.pay2
SELECT @.output
John
<ksrajalakshmi@.gmail.com> wrote in message
news:1139650655.809064.217710@.f14g2000cwb.googlegroups.com...
> If am having the value as
> string strvalue ="(12.23+233.56)*12/100";
> i've to find the value.so that am converting to double. but it throws
> error. tel me how to find value?
>|||Actually I meant that your syntax wasn't SQL syntax:
Not mine. It is T-SQL :)
----
Louis Davidson - http://spaces.msn.com/members/drsql/
SQL Server MVP
"Arguments are to be avoided: they are always vulgar and often convincing."
(Oscar Wilde)
"Louis Davidson" <dr_dontspamme_sql@.hotmail.com> wrote in message news:...
> First, this clearly isn't SQL Syntax, but that notwithstanding, you can
> evaluate a function like this, (as long as it fits SQL Syntax of course)
> declare @.value decimal (10,8)
> declare @.formula varchar(200), @.query nvarchar(2000)
> set @.formula = '(12.23+233.56)*12/100'
> set @.query = 'select @.value = (' + @.formula + ')'
> EXEC sp_executesql @.query,
> N'@.Value decimal(10,8) output',
> @.value output
> select @.value
> I would strongly suggest against it, since this is really not SQL's
> strongpoint. This is one of the rare cases where I would probably suggest
> you storing the expression and the answer in two columns (using the middle
> tier layer to calculate the value, or this method could be used in a a
> singleton insert.)
>
> --
> ----
--
> Louis Davidson - http://spaces.msn.com/members/drsql/
> SQL Server MVP
> "Arguments are to be avoided: they are always vulgar and often
> convincing."
> (Oscar Wilde)
> <ksrajalakshmi@.gmail.com> wrote in message
> news:1139650655.809064.217710@.f14g2000cwb.googlegroups.com...
>|||First, this clearly isn't SQL Syntax, but that notwithstanding, you can
evaluate a function like this, (as long as it fits SQL Syntax of course)
declare @.value decimal (10,8)
declare @.formula varchar(200), @.query nvarchar(2000)
set @.formula = '(12.23+233.56)*12/100'
set @.query = 'select @.value = (' + @.formula + ')'
EXEC sp_executesql @.query,
N'@.Value decimal(10,8) output',
@.value output
select @.value
I would strongly suggest against it, since this is really not SQL's
strongpoint. This is one of the rare cases where I would probably suggest
you storing the expression and the answer in two columns (using the middle
tier layer to calculate the value, or this method could be used in a a
singleton insert.)
----
Louis Davidson - http://spaces.msn.com/members/drsql/
SQL Server MVP
"Arguments are to be avoided: they are always vulgar and often convincing."
(Oscar Wilde)
<ksrajalakshmi@.gmail.com> wrote in message
news:1139650655.809064.217710@.f14g2000cwb.googlegroups.com...
> If am having the value as
> string strvalue ="(12.23+233.56)*12/100";
> i've to find the value.so that am converting to double. but it throws
> error. tel me how to find value?
>