Friday, March 23, 2012

Find website from email address

Hi,

I have 2 fields in a database: 'email' and 'website'.

In the majority of cases, the website field is not populated even though the
email address is. In 90% of cases, the website will be 'www.' followed by
whatever is after the '@.' symbol in the email address.

Would anyone be able to help me with the SQL that would take whatever is
after the '@.' sign in the email address, add it to 'www.' and populate the
'website' field?

Thanks!Would anyone be able to help me with the SQL that would take whatever

Quote:

Originally Posted by

is after the '@.' sign in the email address, add it to 'www.' and
populate the 'website' field?


UPDATE yourtable
SET Site = SUBSTRING(yourtable.email, CHARINDEX('@.', yourtable.email) + 1,
LEN(yourtable.email) - CHARINDEX('@.', yourtable.email))

--
PBsoft di Gabriele Bertolucci
www.pbsoft.it
skype:pbsoftsolution|||Would anyone be able to help me with the SQL that would take whatever is

Quote:

Originally Posted by

after the '@.' sign in the email address, add it to 'www.' and populate the
'website' field?


Here's one method:

UPDATE dbo.MyTable
SET website =
CASE WHEN CHARINDEX('@.', email) 0 AND CHARINDEX('@.', email) + 1 <
LEN(email) THEN
'www.' + SUBSTRING(email, CHARINDEX('@.', email) + 1, 255)
ELSE
website
END
WHERE
website IS NULL OR
website = ''

--
Hope this helps.

Dan Guzman
SQL Server MVP

"Mintyman" <mintyman@.ntlworld.comwrote in message
news:f6gap5$qgb$1$8300dec7@.news.demon.co.uk...

Quote:

Originally Posted by

Hi,
>
I have 2 fields in a database: 'email' and 'website'.
>
In the majority of cases, the website field is not populated even though
the email address is. In 90% of cases, the website will be 'www.' followed
by whatever is after the '@.' symbol in the email address.
>
Would anyone be able to help me with the SQL that would take whatever is
after the '@.' sign in the email address, add it to 'www.' and populate the
'website' field?
>
Thanks!
>

|||Cheers guys! Much appreciated :o)

"Mintyman" <mintyman@.ntlworld.comwrote in message
news:f6gap5$qgb$1$8300dec7@.news.demon.co.uk...

Quote:

Originally Posted by

Hi,
>
I have 2 fields in a database: 'email' and 'website'.
>
In the majority of cases, the website field is not populated even though
the email address is. In 90% of cases, the website will be 'www.' followed
by whatever is after the '@.' symbol in the email address.
>
Would anyone be able to help me with the SQL that would take whatever is
after the '@.' sign in the email address, add it to 'www.' and populate the
'website' field?
>
Thanks!
>

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